Now we have everything to compute the skating torque
T and its projection to the stylus
Fs!
$$T={\mu \cdot F \cdot L} \qquad F_s={T \over SA}\qquad \text{so} \;\; F_s={\mu \cdot F {L \over SA}}$$
And with our actual numbers:
$$F_s={0.3 \cdot 2 \cdot {86 \over 229}} \qquad F_s = 0.23\;gf$$
The side force acting on a stylus is approximately 0.23 gram-force when the downforce is set to 2 gram-force. If we look beyond the null points and account for a worst case ±1° tracking error, the skating force would change about ±0.01 gf — not significant at all. Remember, the starting torque ("stickiness") of good tonearm bearings
is about 40 mg at the stylus. That's 0.04 gf, four times more than the change in the skating force over the whole arc.
The antiskating force should be exactly the same, just applied in an opposite direction. I wonder how much force actual tonearms apply with antiskating set to "2"?