I am not a maths wizard, and I have asked a brilliant engineer
Mr Alexander Valencia-Campo to help me with derivation. Here's what he came up with:
$$A_{b} = A_{a}w_{0}^{2}\dfrac{1}{\sqrt{ (w_{0}^{2} - w^{2})^{2} + w^{2}w_{0}^{2}/Q^{2} }}$$
\(A_{a}\) is amplitude with which the external force excites point
A (the stylus motion, basically)
\(A_{b}\) is the resulting amplitude in point
B (how far the tonearm deflects as measured at headshell)
\(Q\) is the damping factor
\(w\) is the frequency with which point
A moves
\(w_{0}\) is the system's natural frequency \(\sqrt{c \over m}\). Exactly the same as in Carlson's formula, only written in terms of angular frequency instead of Hertz. It's worth noting that once we start to account for losses and introduce
Q, it's no longer the same as the system's resonant frequency. Here's how they are related:
$$w_{res}=w_{0}\sqrt{1-\dfrac{ 1}{2Q^{2}}}$$
The derivation is available in a
linked PDF file.